[YodasLuke]

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I have previously thought that it relates to the COG of the clubhead's mass relative to the hosel, and I have presumed that the offset COG of the clubhead causes the clubhead to swivel around the clubshaft's axis.

I'm aware that I'm beating the dead horse into glue. But, there's a concept that must be understood. My goal is to clearly state an idea, not to beat you (Jeff) or your ideas into the ground. I wasn't born with these ideas. Thanks to Homer and Lynn, I have a much better understanding.

The Clubshaft is not the axis of rotation. It is the club's COG that is the axis of rotation. It's a stumbling block that is supported by the use of a Plane board.

Many times, I've used the example of a lathe. A baseball bat is symmetrical, and it's made on a lathe. When the bat is finished, it can be spun at any speed (RPM's) and it doesn't wobble. A golf club is not symmetrical. If you place the golf club on the lathe and use the shaft as its axis of rotation, you need to seek cover when it's spun at high speed. On the other hand, if you use the club's COG (a line from the #3 Pressure Point to the Sweet Spot) as the axis of rotation, you can stand and watch. There's no danger of the club flying off the lathe.

Using the Clubshaft as the axis or rotation is not logical. If we assume that your argument above is true, you would assume the force that would quickly swivel the Clubhead around the Clubshaft would be a divergent force vector. The resulting wobble would pull the Clubshaft off of the Plane Line that you were attempting to trace. It results in scattered force vectors, and a less than perfect application for compression. It is the club's COG that must trace a straight Plane Line, not the Clubshaft.

Are we even remotely in agreement?